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Nimbuzz: Anyone who can help me?



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#1
Fuera de línea
on Sun Jun 26, 2016 12:51 am


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KßZ ►☻◄ ƒøяυλ⁄(-мємвєя

KßZ ►☻◄ ƒøяυλ⁄(-мємвєя
I'm creating new mobile server bot using C# and agsxmpp.  so i want to allow my bot to accept friend requests but i'm  new to nimbuzz related programming, so anyone who can help me or give me code for accepting friend requests?

Please ur help as soon u see my question.
------
regard Sehdi Sufi.

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#2
Fuera de línea
on Tue Jun 28, 2016 2:00 am


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KßZ ►☻◄ ƒøяυλ⁄(-мємвєя

KßZ ►☻◄ ƒøяυλ⁄(-мємвєя
hello bro
here is complete server bot code
hope you will find all what you want
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#3
Fuera de línea
on Thu Jun 30, 2016 10:29 pm


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KßZ ►☻◄ ƒøяυλ⁄(-мємвєя

KßZ ►☻◄ ƒøяυλ⁄(-мємвєя
Hi sehdi, you can use this code  to auto accept your bot new  users.



Code:
if (InvokeRequired)
                BeginInvoke(new agsXMPP.protocol.client.PresenceHandler(Presence), new object[] { sender, ac });
            else
            {
                if (ac.Type == agsXMPP.protocol.client.PresenceType.subscribe)
                {

                    agsxm.Send("<presence to=\"" + ac.From + "\" type=\"subscribed\" />" +
                        "<presence to=\"" + ac.From + "\" type=\"subscribe\" />");
                    agsxm.Send(new agsXMPP.protocol.client.Message(new agsXMPP.Jid(ac.From.User+"@nimbuzz.com"), agsXMPP.protocol.client.MessageType.chat,"Hi, user! \nSend 'HELP' to get started."));                
                }
            }




replace"agsxm" with your declared "agsXMPP" connection.

If you need to leant C# programming(with complete videos and source codes) to expert download "csharp teacher" from this link

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#4
Fuera de línea
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