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KßZ ►☻◄ ƒøяυλ⁄(-мємвєя
KßZ ►☻◄ ƒøяυλ⁄(-мємвєя
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sehdi
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Topic Nimbuzz: Anyone who can help me?

on Sun Jun 26, 2016 12:51 am
I'm creating new mobile server bot using C# and agsxmpp.  so i want to allow my bot to accept friend requests but i'm  new to nimbuzz related programming, so anyone who can help me or give me code for accepting friend requests?

Please ur help as soon u see my question.
------
regard Sehdi Sufi.
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KßZ ►☻◄ ƒøяυλ⁄(-мємвєя
KßZ ►☻◄ ƒøяυλ⁄(-мємвєя
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ali
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Topic Re: Nimbuzz: Anyone who can help me?

on Tue Jun 28, 2016 2:00 am
hello bro
here is complete server bot code
hope you will find all what you want
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KßZ ►☻◄ ƒøяυλ⁄(-мємвєя
KßZ ►☻◄ ƒøяυλ⁄(-мємвєя
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Ibuzz Software
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Topic Re: Nimbuzz: Anyone who can help me?

on Thu Jun 30, 2016 10:29 pm
Hi sehdi, you can use this code  to auto accept your bot new  users.



Code:
if (InvokeRequired)
                BeginInvoke(new agsXMPP.protocol.client.PresenceHandler(Presence), new object[] { sender, ac });
            else
            {
                if (ac.Type == agsXMPP.protocol.client.PresenceType.subscribe)
                {

                    agsxm.Send("<presence to=\"" + ac.From + "\" type=\"subscribed\" />" +
                        "<presence to=\"" + ac.From + "\" type=\"subscribe\" />");
                    agsxm.Send(new agsXMPP.protocol.client.Message(new agsXMPP.Jid(ac.From.User+"@nimbuzz.com"), agsXMPP.protocol.client.MessageType.chat,"Hi, user! \nSend 'HELP' to get started."));                
                }
            }




replace"agsxm" with your declared "agsXMPP" connection.

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Topic Re: Nimbuzz: Anyone who can help me?

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